PHP: mcal_day_of_week

mcal_day_of_week

ssimon at latinschool dot org
04-Aug-2003 08:29


If you don't have mcal, and need a replacement, here is an even easier way:



<?php



$utime = mktime (1,1,1,$month,$day,$year);

$weekday=date('w',$utime);   //  0 for Sunday through 6 for Saturday, just like mcal_day_of_week



?>

mail at azov dot info
30-Jul-2003 05:17


I did it much easier (without "mcal" library):



function convertday($n){



switch ($n){

case "Mon": return "Monday";break;

case "Tue": return "Tuesday";break;

case "Wed": return "Wednesday";break;

case "Thu": return "Thursday";break;

case "Fri": return "Friday";break;

case "Sat": return "Saturday";break;

case "Sun": return "Sunday";break;

};



};



function curdate(){



$ret=date("d-m-Y").", ".convertday(date("D"));



return $ret;

};

cigalcohol at yahoo dot com
10-Aug-2002 02:35


I don't have the MCAL lib, so I wrote a script that will return the day of the week for any date 2000+ using Zeller's Rule:



http://mathforum.org/dr.math/faq/faq.calendar.html



I only needed it to work for this century, so I replaced a few variables with constants, and I split up the equation itself into its component parts because I'm something of a n00b and I get condused easily.



$y needs to be two digits, not four, eg, "02", "13", vs 2002, 2013, &c.



<?



if ( $m >= "3") {

     $mn = $m - 2; }

else {

     $mn = $m + 10; }



if ( $mn >= "11" ) {

     $yn = $y - 1; }

else { $yn = $y; }



$rem = $d;



$rem =  floor((13*$mn-1)/5) + $rem;



$rem = $rem + $yn;



$rem = floor($yn/4) + $rem;



$rem = $rem  - 35;



$rem = $rem % 7;



if ($rem < 0) {

     $rem = $rem + 7;}



if ($rem == "0") { $w = "Sun"; }

elseif ($rem == "1") { $w = "Mon"; }

elseif ($rem == "2") { $w = "Tue"; }

elseif ($rem == "3") { $w = "Wed"; }

elseif ($rem == "4") { $w = "Thu"; }

elseif ($rem == "5") { $w = "Fri"; }

elseif ($rem == "6") { $w = "Sat"; }



echo "$m.$d.$y is a $w";



?>

dagjo at stud dot ntnu dot no
03-Jun-2001 11:57


It is quite straightforward... Here's an example:





<?php





$year = strftime('%Y');


$month = strftime('%m'); 


$day = strftime('%d');





$weekDay = mcal_day_of_week($year, $month, $day);





switch ($weekDay) {


case 0:


print("Today is Sunday");


break;





case 1:


print("Today is Monday");


break;


    


...


    


case 6:


print("Today is Saturday");


break;


} // end switch





?>

mcal_day_of_week

Description