mysqli_stmt_affected_rows

(PHP 5)

mysqli_stmt_affected_rows

(no version information, might be only in CVS)

mysqli_stmt->affected_rows -- Returns the total number of rows changed, deleted, or inserted by the last executed statement

Description

Procedural style :

int mysqli_stmt_affected_rows ( mysqli_stmt stmt )

Object oriented style (property):

class mysqli_stmt {

int affected_rows

}

mysqli_stmt_affected_rows() returns the number of rows affected by INSERT, UPDATE, or DELETE query. If the last query was invalid, this function will return -1.

The mysqli_stmt_affected_rows() function only works with queries which update a table. In order to return the number of rows from a SELECT query, use the mysqli_stmt_num_rows() function instead.

Возвращаемые значения

An integer greater than zero indicates the number of rows affected or retrieved. Zero indicates that no records where updated for an UPDATE/DELETE statement, no rows matched the WHERE clause in the query or that no query has yet been executed. -1 indicates that the query has returned an error.

Замечание: If the number of affected rows is greater than maximal PHP int value, the number of affected rows will be returned as a string value.

Смотрите также

mysqli_stmt_num_rows() и mysqli_prepare().

Примеры

Пример 1. Object oriented style

<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
   printf("Connect failed: %s\n", mysqli_connect_error());
   exit();
}

/* create temp table */
$mysqli->query("CREATE TEMPORARY TABLE myCountry LIKE Country");

$query = "INSERT INTO myCountry SELECT * FROM Country WHERE Code LIKE ?";

/* prepare statement */
if ($stmt = $mysqli->prepare($query)) {

   /* Bind variable for placeholder */
   $code = 'A%';
   $stmt->bind_param("s", $code);
  
   /* execute statement */
   $stmt->execute();

   printf("rows inserted: %d\n", $stmt->affected_rows);

   /* close statement */
   $stmt->close();
}

/* close connection */
$mysqli->close();
?>

Пример 2. Procedural style

<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
   printf("Connect failed: %s\n", mysqli_connect_error());
   exit();
}

/* create temp table */
mysqli_query($link, "CREATE TEMPORARY TABLE myCountry LIKE Country");

$query = "INSERT INTO myCountry SELECT * FROM Country WHERE Code LIKE ?";

/* prepare statement */
if ($stmt = mysqli_prepare($link, $query)) {

   /* Bind variable for placeholder */
   $code = 'A%';
   mysqli_stmt_bind_param($stmt, "s", $code);
  
   /* execute statement */
   mysqli_stmt_execute($stmt);

   printf("rows inserted: %d\n", mysqli_stmt_affected_rows($stmt));

   /* close statement */
   mysqli_stmt_close($stmt);
}

/* close connection */
mysqli_close($link);
?>

Результат выполнения данного примера:

rows inserted: 17


mysqli_stmt_affected_rows
Carl Olsen
27-Dec-2005 10:34
It appears that an UPDATE prepared statement which contains the same data as that already in the database returns 0 for affected_rows.  I was expecting it to return 1, but it must be comparing the input values with the existing values and determining that no UPDATE has occurred.

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 Last updated: Tue, 15 Nov 2005