PHP: date - Manual

Описание

string date ( string format [, int timestamp] )

Возвращает время, отформатированное в соответствии с аргументом format, используя метку времени, заданную аргументом timestamp или текущее системное время, если timestamp не задан. Другими словами, timestamp является необязательным и по умолчанию равен значению, возвращаемому функцией time().

Замечание: Для большинства систем допустимыми являются даты с 13 декабря 1901, 20:45:54 GMT по 19 января 2038, 03:14:07 GMT. (Эти даты соответствуют минимальному и максимальному значению 32-битового целого со знаком). Для Windows допустимы даты с 01-01-1970 по 19-01-2038.

Замечание: Для получения метки времени из строкового представления даты можно использовать функцию strtotime(). Кроме того, некоторые базы данных имеют собственные функции для преобразования внутреннего представления даты в метку времени (напрмер, функция MySQL UNIX_TIMESTAMP).

Таблица 1. В параметре format распознаются следующие символы

Символ в строке `format`	Описание	Пример возвращаемого значения
`a`	Ante meridiem или Post meridiem в нижнем регистре	`am` или `pm`
`A`	Ante meridiem или Post meridiem в верхнем регистре	`AM` или `PM`
`B`	Время в стадарте Swatch Internet	От `000` до `999`
`c`	Дата в формате ISO 8601 (добавлено в PHP 5)	2004-02-12T15:19:21+00:00
`d`	День месяца, 2 цифры с ведущими нулями	от `01` до `31`
`D`	Сокращенное наименование дня недели, 3 символа	от `Mon` до `Sun`
`F`	Полное наименование месяца, например January или March	от `January` до `December`
`g`	Часы в 12-часовом формате без ведущих нулей	От `1` до `12`
`G`	Часы в 24-часовом формате без ведущих нулей	От `0` до `23`
`h`	Часы в 12-часовом формате с ведущими нулями	От `01` до `12`
`H`	Часы в 24-часовом формате с ведущими нулями	От `00` до `23`
`i`	Минуты с ведущими нулями	`00` to `59`
`I` (заглавная i)	Признак летнего времени	`1`, если дата соответствует летнему времени, иначе `0` otherwise.
`j`	День месяца без ведущих нулей	От `1` до `31`
`l` (строчная 'L')	Полное наименование дня недели	От `Sunday` до `Saturday`
`L`	Признак високосного года	`1`, если год високосный, иначе `0`.
`m`	Порядковый номер месяца с ведущими нулями	От `01` до `12`
`M`	Сокращенное наименование месяца, 3 символа	От `Jan` до `Dec`
`n`	Порядковый номер месяца без ведущих нулей	От `1` до `12`
`O`	Разница с временем по Гринвичу в часах	Например: `+0200`
`r`	Дата в формате RFC 2822	Например: `Thu, 21 Dec 2000 16:01:07 +0200`
`s`	Секунды с ведущими нулями	От `00` до `59`
`S`	Английский суффикс порядкового числительного дня месяца, 2 символа	`st`, `nd`, `rd` или `th`. Применяется совместно с `j`
`t`	Количество дней в месяце	От `28` до `31`
`T`	Временная зона на сервере	Примеры: `EST`, `MDT` ...
`U`	Количество секунд, прошедших с начала Эпохи Unix (The Unix Epoch, 1 января 1970, 00:00:00 GMT)	См. также time()
`w`	Порядковый номер дня недели	От `0` (воскресенье) до `6` (суббота)
`W`	Порядковый номер недели года по ISO-8601, первый день недели - понедельник (добавлено в PHP 4.1.0)	Например: `42` (42-я неделя года)
`Y`	Порядковый номер года, 4 цифры	Примеры: `1999`, `2003`
`y`	Номер года, 2 цифры	Примеры: `99`, `03`
`z`	Порядковый номер дня в году (нумерация с 0)	От `0` до `365`
`Z`	Смещение временной зоны в секундах. Для временных зон западнее UTC это отрицательное число, восточнее UTC - положительное.	От `-43200` до `43200`

Любые другие символы, встреченные в строке format, будут выведены в результирующую строку без изменений. Z всегда возвращает 0 при использовании gmdate().

Пример 1. Примеры использования функции date()

<?php // вывод дня недели, например Wednesday echo date("l"); // вывод даты в формате: Wednesday 15th of January 2003 05:51:38 AM echo date("l dS of F Y h:i:s A"); // вывод: July 1, 2000 is on a Saturday echo "July 1, 2000 is on a " . date("l", mktime(0, 0, 0, 7, 1, 2000)); ?>

Избежать распознавания символа как форматирующего можно, если экранировать этот символ с помощью \ Если в сочетании с \ символ являееся специальным (например, \t), следует добавлять еще один \.
Пример 2. Экранирование символов в функции date()

<?php // вывод: Wednesday the 15th echo date("l \\t\h\e jS"); ?>

Функции date() и mktime() для вывода прошедших и будущих дат.
Пример 3. date() и mktime() example

<?php $tomorrow = mktime(0, 0, 0, date("m") , date("d")+1, date("Y")); $lastmonth = mktime(0, 0, 0, date("m")-1, date("d"), date("Y")); $nextyear = mktime(0, 0, 0, date("m"), date("d"), date("Y")+1); ?>

Замечание: Этот метод более надежен, чем вычитание и прибавление секунд к метке времени, так как mktime() учитывает любые неоднозначности в датах (переход на летнее/зимнее время и др.).

Приведем еще несколько примеров использования функции date(). Помните, что следует экранировать все символы, которые вы хотите видеть в результате работы функции без изменений. Это относится и к символам, которые в текущей версии PHP не распознаются как специальные, так как этим символам может быть назначено значение в следующих версиях. Используйте одинарные кавычки для предотвращения преобразования \n в перевод строки.
Пример 4. Форматирование с использованием date()

<?php // Предположим, что текущая дата March 10th, 2001, 5:16:18 pm $today = date("F j, Y, g:i a"); // March 10, 2001, 5:16 pm $today = date("m.d.y"); // 03.10.01 $today = date("j, n, Y"); // 10, 3, 2001 $today = date("Ymd"); // 20010310 $today = date('h-i-s, j-m-y, it is w Day z '); // 05-16-17, 10-03-01, 1631 1618 6 Fripm01 $today = date('\i\t \i\s \t\h\e jS \d\a\y.'); // It is the 10th day. $today = date("D M j G:i:s T Y"); // Sat Mar 10 15:16:08 MST 2001 $today = date('H:m:s \m \i\s\ \m\o\n\t\h'); // 17:03:17 m is month $today = date("H:i:s"); // 17:16:17 ?>

Для форматирования дат на других языках используйте функции setlocale() и strftime().

См. также описание функций getlastmod(), gmdate(), mktime(), strftime() и time().

date

dulare at gmail dot com
13-Jul-2006 08:36


If You are looking for some simple date calculations:



<?



function days_between($fyear, $fmonth, $fday, $tyear, $tmonth, $tday)

{

  return abs((mktime ( 0, 0, 0, $fmonth, $fday, $fyear) - mktime ( 0, 0, 0, $tmonth, $tday, $tyear))/(60*60*24));

}



function day_before($fyear, $fmonth, $fday)

{

  return date ("Y-m-d", mktime (0,0,0,$fmonth,$fday-1,$fyear));

}



function next_day($fyear, $fmonth, $fday)

{

  return date ("Y-m-d", mktime (0,0,0,$fmonth,$fday+1,$fyear));

}



function weekday($fyear, $fmonth, $fday) //0 is monday

{

  return (((mktime ( 0, 0, 0, $fmonth, $fday, $fyear) - mktime ( 0, 0, 0, 7, 17, 2006))/(60*60*24))+700000) % 7;

}



function prior_monday($fyear, $fmonth, $fday)

{

  return date ("Y-m-d", mktime (0,0,0,$fmonth,$fday-weekday($fyear, $fmonth, $fday),$fyear));  

}



?>

Aristia
08-Jul-2006 11:12


I wrote a small function for calculating birthdays. The days count doesn't seem accurate but the years and months are correct. It seems to be rough around the edges but it works for me :)



function elapsed($year, $month, $day) {

$bdaystamp = mktime(0,0,0, $month, $day, $year);

$today = date("U");

$elapsed = $today - $bdaystamp;

$years_remainder = $elapsed%31536000;

$rawyears = $elapsed-$years_remainder;

$years = $rawyears/31536000;

$months_remainder=$years_remainder%2628000;

$rawmonths =  $years_remainder-$months_remainder;

$months = $rawmonths/2628000;

$days_remainder=$months_remainder%86400;

$rawdays =  $months_remainder-$days_remainder;

$days = $rawdays/86400;

$yearword = "Years";

$monthword = "Months";

$daysword = "Days";

$age= $years.' '.$yearword.' '.$months.'  '.$monthword.' '.$days.' '.$daysword.'';

return $age;

}



$age=elapsed("1978", "01", "18");

piranha-php_manual at thoughtcrime dot us
07-Jul-2006 01:10


hsinche,



Your code is incorrect.  You add 86400 * 7 in at least one place to find the point in time exactly one week in the future.  In the following circumstances, the difference between one Friday and the same time of day on the following Friday is not 86400 * 7 seconds:



  * A daylight savings switch has occurred.  One additional hour (3600 seconds) has been added or lost, offsetting the time of your following Friday by that amount.

  * A leap year correction has been executed--e.g. on December 31st 2005, there were 86401 seconds.  The clock continued onto 23:59:60 before reaching 00:00:00.



This may not mean much in your code, but it spells all kinds of trouble if you ever want to compare the result of a similar calculation with a known value, or your time-of-day falls either on or just before midnight, or any other time when the accuracy of the time-of-day matters in your application.



Although the discrete timescale (n seconds) is linear and infinite and intuitive; it does not map to the calendar and time-of-day systems, which have a laundry list of special rules, added up over time, all to varying ends.



This is why you want to use your system's calendar functions for almost all time manipulation, unless you understand the consequences and they simply don't apply, or unless you're willing to implement the chaotic and arbitrary semantic nuances of the calendar and time-of-day system yourself.

hsinche +at+ yahoo +dot+ com
05-Jul-2006 11:29


<?php

// revolving Friday code

//

// This script displays this coming Friday's date, unless it

// is Friday after 9:45am, when it should show the next Friday's date.

// Alternatively, you can pass an hour and minute to the function.

    

function getFriday($hour = 9, $minute = 45) {

    $day = 60 * 60 * 24; // 1 day is 60 seconds * 60 minutes * 24 hours

    

    switch(date("l")) {

    case "Friday":

    

        $h = date("G");

        

        switch(TRUE) {

        case $h < $hour:

        case ($h == $hour && date("i") < $minute):

            $nextDate = date("F j, Y");

            break;

        default:

            $t = time() + (7 * $day);

            $nextDate = date("F j, Y", $t);

        }

        break;

    default:

        $mod = 5 - date("w");

        if($mod < 0) {

            $mod = 6;

        }

        $t = time() + ($mod * $day);

        $nextDate = date("F j, Y", $t);

    }

    

    echo $nextDate;

}

?>

tam at zenology dot co dot uk
17-May-2006 06:02


/* Here's a simple function which takes a UNIX timestamp and returns a fuzzy date string such as 'Yesterday 10:24', 'Wednesday 23:11', 'April 12' or 'June 2003'. It's only set up to handle dates in the past but it's easy to see how to extend it to do future dates too. */



function fuzzyDate($timestamp)

{

  if($timestamp > time()) 

     //we don't handle future dates

     return date('Y-m-d H:i', $timestamp);

  elseif($timestamp > mktime(0,0,0))

     //since midnight so it's today

     return 'Today '.date('H:i', $timestamp);

  elseif($timestamp > mktime(0,0,0) - 86400) 

     //since midnight 1 day ago so it's yesterday

     return 'Yesterday '.date('H:i', $timestamp);

  elseif($timestamp > mktime(0,0,0) - 86400*7)

     //since midnight 7 days ago so it's this week

     return date('l H:i', $timestamp);

  elseif($timestamp > mktime(0,0,0,1,1))

     //since 1st Jan so it's this year

     return date('F j', $timestamp);

  else

     //ages ago!

     return date('F Y', $timestamp);

}

Elena S.
05-May-2006 02:36


If you do not PHP5 yet but want a week day to be in ISO format: 1 (for Monday) through 7 (for Sunday), you can use this:

<?



//GET WEEK DAY 0 FOR SUNDAY, 6 FOR SATURDAY

$x = date( "w" );



$corrected_week_day = 7 - ( (7-$x) % (7+$x) );



?>

mel dot boyce at gmail dot com
06-Apr-2006 04:46


I've been flicking through the comments looking for some succinct date code and have noticed an alarming number of questions and over-burdened examples related to date mathematics. One of the most useful skills you can utilize when performing date math is taking full advantage of the UNIX timestamp. The UNIX timestamp was built for this kind of work.



An example of this relates to a comment made by james at bandit-dot-co-dot-en-zed. James was looking for a way to calculate the number of days which have passed since a certain date. Rather than using mktime() and a loop, James can subtract the current timestamp from the timestamp of the date in question and divide that by the number of seconds in a day:

<?php

$days = floor((time() - strtotime("01-Jan-2006"))/86400);

print("$days days have passed.\n");

?>



Another usage could find itself in a class submitted by Kyle M Hall which aids in the creation of timestamps from the recent past for use with MySQL. Rather than the looping and fine tuning of a date, Kyle can use the raw UNIX timestamps (this is untested code):

<?php

$ago = 14; // days

$timestamp = time() - ($ago * 86400);

?>



Hopefully these two examples of "UNIX-style" timestamp usage will help those finding date mathematics more elusive than it should be.

SpikeDaCruz
09-Mar-2006 11:12


The following function will return the date (on the Gregorian calendar) for Orthodox Easter (Pascha).  Note that incorrect results will be returned for years less than 1601 or greater than 2399. This is because the Julian calendar (from which the Easter date is calculated) deviates from the Gregorian by one day for each century-year that is NOT a leap-year, i.e. the century is divisible by 4 but not by 10.  (In the old Julian reckoning, EVERY 4th year was a leap-year.)



This algorithm was first proposed by the mathematician/physicist Gauss.  Its complexity derives from the fact that the calculation is based on a combination of solar and lunar calendars.



<?

function getOrthodoxEaster($date){

  /*

   Takes any Gregorian date and returns the Gregorian

   date of Orthodox Easter for that year.

  */

  $year = date("Y", $date);

  $r1 = $year % 19;

  $r2 = $year % 4;

  $r3 = $year % 7;

  $ra = 19 * $r1 + 16;

  $r4 = $ra % 30;

  $rb = 2 * $r2 + 4 * $r3 + 6 * $r4;

  $r5 = $rb % 7;

  $rc = $r4 + $r5;

  //Orthodox Easter for this year will fall $rc days after April 3

  return strtotime("3 April $year + $rc days");

}

?>

rob at robmacdonald dot com
05-Feb-2006 02:24


This function takes a YEARWEEK value (most commonly returned from mysql) and examines it to get the start date and end date for the given YEARWEEK. May be of use to someone...



function findWeekPeriod($yearweek){   

    $aPeriod = array(); 

    $year = substr($yearweek,0,4); 

    $week = substr($yearweek,4,2); 

     

    $startDay = Mon; 

    $endDay = Sun; 



    $startdate =  strtotime('+' . $week . ' week',mktime(0,0,0,1,1,$year));  

     

    $enddate = $startdate; 

    while(date("D",$startdate) != $startDay){ 

        $startdate = mktime(0,0,0,date("m",$startdate),date("d",$startdate)-1, date("Y",$startdate));       

    } 

    while(date("D",$enddate) != $endDay){ 

        $enddate = mktime(0,0,0,date("m",$enddate),date("d",$enddate)+1, date("Y",$enddate));       

    } 



    return array('start' => date('l d/m/y', $startdate),  

                 'end'   => date('l d/m/y', $enddate));  



   return $aPeriod; 

}

erwinmoller at xs4all dot nl
05-Jan-2006 04:34


If you need dates that are prior to 1970 (or 1901 for php5.1), have a look at calendar at this very site:

calendar

martin dot m at hid dot gr
19-Dec-2005 08:25


"It worked ok, except I noticed it had some trouble if you were spanning months, (i.e. 03-29-2005 to 04-10-2005)"



this is the (Daylight Saving Time ) problem. you can check if the start date and the end date are 

whether or not in daylights savings time by using 

date('I',$your_date) and to add or decrease with one hour.

Nick H
24-Nov-2005 06:21


Users in GMT may find some information on British Summer Time useful. Personally I was confused that date() for a timestamp of 0 was returning 1am, until I found about the all-year BST from 1968-71.



http://wwp.greenwichmeantime.com/info/bst2.htm

itsacon at itsacon dot net
16-Nov-2005 02:28


Caveat when using the 'W' and 'w' options together:



The 'W' option uses the ISO-8601 standard (week ends on sunday), whereas the 'w' option has the week _start_ on sunday (sunday == 0).

vernon at vernonkesner dot com
02-Nov-2005 09:37


The examples for getting a date in the past or future is simply not the best way to do it.  Especially if you are doing it dynamically.



I find the best way to get a date in the past or future is like this:



<?php

//get timestamp for past/future date I want

$pf_time = strtotime("-3 days");

//format the date using the timestamp generated

$pf_date = date("Y-m-d", $pf_time);

?>

martin at kurahaupo dot gen dot nz
30-Oct-2005 01:52


There is a mistaken impression that the maximum difference between UTC and localtime is +/- 12 hours. Right now it is summer here in New Zealand, and we're 13 hours ahead of UTC, and further east in the Chatham Islands it's UTC+13:45.



Consequently, the range for the "Z" conversion is at least -43200 ... +49500

mbirth at webwriters dot de
25-Oct-2005 03:24


Using 'B' for the Swatch Internet Time (i.Beats) can still lead to misunderstandings, because the date given in the resulting string is the local date, not the date of the BMT (Biel Mean Time / UTC+0100) after which the i.Beats are counted. So while @000 is equal all around the globe, October 25th 2005 @000 in Chicago is really October 24th, 06:00 PM local time.



Otherwise, if you use date('d M Y @B') in Chicago on that day at 6pm, it will return "24 Oct 2005 @000" although it should be "25 Oct 2005 @000".



So it may happen that you miss an appointment by 24 hours (or 1000 Beats ;-)



Here's a way to return the Internet Time with correct date:



<?php

  $curtime = time();

  $utcdiff = date('Z', $curtime);  // get difference to UTC in seconds

  $bmttime = $curtime - $utcdiff + 3600;   // BMT = UTC+0100

  $ssm = date('H', $bmttime)*3600 + date('i', $bmttime)*60 + date('s', $bmttime);  // seconds since midnight (BMT)

  $ibeats = $ssm/86.4;  // 86400 seconds = 1000 beats, so 1 beat = 86.4 seconds



  echo 'i.Beats     : ' . date('D, d M Y', $bmttime) . ' @' . $ibeats;

?>



Note: If you would try date('D, d M Y @B', $bmttime), the resulting beats would be wrong because the timezone used for calculation of the beats within the date() function is still your local one but the timestamp is UTC+0100. Another working way would be:



<?php

  $curtime = time();

  $utcdiff = date('Z', $curtime);  // get difference to UTC in seconds

  $bmttime = $curtime - $utcdiff + 3600;   // BMT = UTC+0100



  echo 'i.Beats     : ' . date('D, d M Y', $bmttime) . ' @' . date('B', $curtime);

?>



But this way there are no floating-point beats possible, which may be handy sometimes.

mendoza at pvv dot ntnu dot no
13-Oct-2005 10:38


At "daykay at pdsoftware dot de":



09 != 9 so there's nothing wrong about European vs. American formats.



$ php -r 'print 09; print "\n"; print 9; print "\n";'

0

9



09 is treated as octal and since octal numbers only use the 0-7 digits, it evaluates to 0. All numbers prefixed with 0 are considered octal just as 0x are considered hexadecimal.



http://en.wikipedia.org/wiki/Computer_numbering_formats

jim at catsanddogs dot com
12-Oct-2005 03:52


To get the start date for a working week:



<?php



list($iDay, $iMonth, $iYear) = split('-', date('d-m-Y', mktime(0, 0, 0, date('n'), ((date('j')+1)-date('w')), date('Y'))));



return $iDay.'-'.$iMonth.'-'.$iYear;



?>

kbrill at multi dot com
15-Sep-2005 08:27


I created a routine that fills an array with the dates in the current week.  For example $WeekDays[0] is sunday's date, $WeekDays[1] is monday's date and so on no matter what day of the week it is today.



<?php

        $lowEnd=date("w");

        $lowEnd=-$lowEnd;

        $highEnd=$lowEnd + 6;

        $weekday=0;

        for ($i=$lowEnd; $i<=$highEnd; $i++) {

            $WeekDate[$weekday]=date("m/d",mktime(0, 0, 0, date("m")  , date("d")+$i, date("Y")));

            $weekday++;

        }

?>

webmaster [AT] gn-solutions [DOT] de
07-Sep-2005 04:19


For users who want a different language than english, you can user strftime() function in combination with setlocale() instead of date():



e.g. for german language:



With date you would write:

<?php

echo date('l, d. F Y'); //Output: Wednesday, 07. September 2005

?>



With strftime() you can output it in german like this:

<?php

// Set the gloabal LC_TIME constant to german

setlocale(LC_TIME, 'de_DE');

// Little bit other Syntax but better effect

echo strftime('%A, %d. %B %Y'); //Output: Mittwoch, 07. September 2005

?>



Greetings, Andy!

steve at somejunkwelike dot com
16-Aug-2005 11:01


re: Paul_liversidge...



This is a way to get the next 10 business days, by comparing the day of the week to not be saturday or sunday.  change the top two variables to get various different results...  if you want to get the next 10 business days, starting in two days from today, change the first variable to 2, and the second to 14.  This should yield the next 10 working days.



<?php 



$how_many_business_days_ahead = 0;

$how_many_business_days_to_count = 7;



for ($i=0;$i<$how_many_business_days_to_count;$i++)

    {

    $jump=$i+$how_many_business_days_ahead;

    $evalday = mktime(strftime ("%d/%m/%Y", strtotime("+$jump days")));

    $theday = strftime("%A", strtotime("+$jump days"));    

    if($theday != "Saturday" and $theday != "Sunday")

        {

        $days = $how_many_business_days_ahead+$i;

        $the_days[$j] = strftime("%A, %B %d, %Y", strtotime("+$jump days"));

        $j++;

        }

    }

    

    $k = $how_many_business_days_ahead;

    

    foreach($the_days as $eachday)

        {

        echo "$k business days from now = $eachday<br />";

        $k++;

        }

    

    

?>



results:



0 business days from now = Tuesday, August 16, 2005

1 business days from now = Wednesday, August 17, 2005

2 business days from now = Thursday, August 18, 2005

3 business days from now = Friday, August 19, 2005

4 business days from now = Monday, August 22, 2005

Rob Muhlestein
05-Aug-2005 10:48


All functions that have anything to do with the internal 32-bit constrained time() system call will have this same limitation. Hopefully we'll be 64 bit by long before then, although this already creating problems with UNIX internals.

ove at junne dot dk
02-Aug-2005 11:39


I seems to me that we're rapidly apporaching another Y2K event. The date-function only handles dates up to 2038, and this is only some 30 years away. Even today is it impossible to use date() to represent my children's 50 years birthday.





Just think about it, when you're designing your code.





[ed.: This limitation is gone in PHP 5.1 and higher, although PHP itself limits integers still to 32bit]

stuff at rushsoft dot de
30-Jun-2005 02:13


ISO 8601:2000 defines:

[...] day of the year is represented by three decimal digits. The first day of any year is represented by [001] and

subsequent days are numbered in ascending sequence [...]



So don't forget increasing the return value of date("z") by one to be ISO conform, if you use this, for instance, on presentation level.

witcho at gmail dot com
07-Jun-2005 09:22


When using 'z' it should be used as how many days have passed since the beginning of the year; not as the day of the year. 

"January 1" is the day 1 of the year not the day 0. 

Better to add 1 when using 'z' if you really want to know the day of the year.

justin at drunkatgt dot com
04-Jun-2005 08:24


In response to pmcdevitt(at)cesales.com:



If you just want to find out what last month was, try

$lastmonth=mktime(0,0,0,date("m")-1,1,date("Y"));

$lastmonth= date("M", $lastmonth);



There is no reason to use the day of the month to determine the revious month.  And every month has a 1st.  You could even through an arbitrary year in there to save a fraction of a calculation.

MG_Peter at o2 dot pl
30-Apr-2005 05:05


easy way - to convert a "datetime" form mySQL into php date format....

first - get the array form mySQL, then use



<?php

date("d M Y H:i:s", strtotime($your_row['lastlogin_date']))

?>



strtotime - easy converts a datetime timestamp into time  ( time() or date("U")).

llewellyntd at gmail dot com
29-Apr-2005 05:50


Here is a very easy way to get the difference, in days, between two dates:



$days = (strtotime("2005-12-31") - strtotime(date("Y-m-d"))) / (60 * 60 * 24);

print $days;

rcrodgers622 at gmail dot com
25-Mar-2005 10:08


Regarding dolso at elastech dot it's note, it's actually easier to use the 't' item to get the last day of any given month.



echo 'February ' . date('t',mktime(0,0,0,2,1,2004)) . ' is the last day of February 2004'; 

//Displays "The February 29 is the last day of February 2004"



The actual day of the month specified in mktime() is irrelevant, but it's best and safest to use a day that won't alter the results such as the first of the month.

jon AT standardise DOT us
15-Feb-2005 08:57


Don't forget that months start on the 1st day, and not a zero date.  Might seem obvious but:



$test = date("F Y", mktime(0, 0, 0, 12, 0, 2005));



Will return November 2005, not December.



$test = date("F Y", mktime(0, 0, 0, 12, 1, 2005));



The 1st is needed to get the right month.

ag nodot nospam at netside dot de
28-Jan-2005 07:19


Calculus of weeks in a year.



Since there is date("W") many still seem to have a problem regarding how many weeks there are in an year. Some rather complex solutions have been shown here.



It's defined, that a week which begins in december and ends in january the following year belongs to the year where most of its days lie. Therefore a week with at least 4 days in december is the last week of that year and a week with at least 4 days in january is the first week in the new year.



This concludes, that the last week of a year always contains the 28th day of december. So if you take date("W") on that day of a given year you always get the correct number of weeks for that year.

The other end of that definition is that the 4th day of january always lies in the first week of a year.



I hope this solves a lot of confusion.



(For those asking what all this fuzz about counting weeks is about: normally theres 52 weeks in a year but sometimes its 53 weeks in a year)



I wrote it down as a function, but as this is rather trivial one might consider using the date(...) only.



function weeks($year) {

    return date("W",mktime(0,0,0,12,28,$year));

}

milad[at]rastian[dot]com
24-Dec-2004 01:40


All irainain who want use Jalali Date:

see this site : http://jdf.farsiprojects.com

I create function such as date in php

php at document-root dot de
14-Apr-2004 10:02


To convert an unix timestamp to suite the syntax of a GeneralizedTime attribute for OpenLDAP, you can use

date ('YmdHiZO'). Note that this conversion uses local time, the recommended way is to store dates in UTC.



If your date is in UTC, just use

date ('YmdHiZ').'Z' to convert it ("Z" stands for "Zulu", which is UTC).

daniel
17-Feb-2004 02:43


The following function will return the date (on the Gregorian calendar) for Orthodox Easter (Pascha).  Note that incorrect results will be returned for years less than 1601 or greater than 2399. This is because the Julian calendar (from which the Easter date is calculated) deviates from the Gregorian by one day for each century-year that is NOT a leap-year, i.e. the century is divisible by 4 but not by 10.  (In the old Julian reckoning, EVERY 4th year was a leap-year.)



This algorithm was first proposed by the mathematician/physicist Gauss.  Its complexity derives from the fact that the calculation is based on a combination of solar and lunar calendars.



<?

function getOrthodoxEaster($date){

  /*

    Takes any Gregorian date and returns the Gregorian

    date of Orthodox Easter for that year.

  */

  $year = date("Y", $date);

  $r1 = $year % 19;

  $r2 = $year % 4;

  $r3 = $year % 7;

  $ra = 19 * $r1 + 16;

  $r4 = $ra % 30;

  $rb = 2 * $r2 + 4 * $r3 + 6 * $r4;

  $r5 = $rb % 7;

  $rc = $r4 + $r5;

  //Orthodox Easter for this year will fall $rc days after April 3

  return strtotime("3 April $year + $rc days");

}

?>